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Sunday 13 February 2022

Gravitation - Physics For Class IX (Science Group) - Numericals

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Physics For Class IX (Science Group)
UNIT 6: GRAVITATION
Numericals


WORKED EXAMPLES


Worked Example 2

2. Calculate the weight of Rumaisa, who has a mass of 65 kg standing at the ground. The strength of gravitational field on Rumaisa is 10 Newton per kilogram?
Solution:

Step 1: Write down known quantities and quantities to be found.
  • m = 65 kg
  • g = 10 Nkg-1
  • W = ?

Step 2: Write down formula and rearrange if necessary
W = mg

Step 3: Put the values in formula and calculate
W = 65 kg x 10 Nkg-1
Ans: Hence, the weight of Rumaisa is 650 Newton.

Worked Example 3

3. Calculate the acceleration due to gravity on a planet that has mass two times to the mass of Earth and radius 1.5 times to the radius of Earth. If the acceleration due to gravity on the surface of Earth is 10 ms-2. Calculate acceleration due to gravity on the planet?
Solution
Step 1: Write down known quantities and quantities to be found.
  • Mass of the planet = Mp = 2 ME
  • Mass of the Earth = ME = 6.0 x 1024 kg
  • Radius of the planet = Rp = 1.5 R E
  • Radius of the Earth = R E = 6.38 x 10m
  • Universal gravitational constant = G = 6.673 x 10-11 Nmkg-2
  • Acceleration due to gravity on the Earth = g E =10 ms-2
  • Acceleration due to gravity on the planet = gp = ?

Step 2: Write down formula and rearrange if necessary
For the Earth:

Ans: Hence, acceleration due to gravity on the planet is 8.74 ms-2.



TEXT BOOK EXERCISE


Section (B) Structured Questions
Newton’s Law of Gravitation
4. Determine the gravitational force of attraction between Urwa and Ayesha standing at a distance of 50 m apart. The mass of Urwa is 60 kg and that of Ayesha is 70 kg.
Solution:
Data:
  1. Mass of Urwa = m1 = 60 kg
  2. Mass of Ayesha = m2 = 70 kg
  3. Distance between Urwa and Ayesha = r = 50 m
  4. Universal gravitation = G = 6.673 x 10-11 Nm2kg-2
  5. Gravitational force = F = ?


Ans: Hence the gravitational force of attraction between Urwa and Ayesha is 1.121064 x 10-10 N.

Weight
6.b) Weight of Rani is 450 N at the surface of Earth. Find her mass?
Solution:
Data:
  • Weight of Rani = 450 N
  • Acceleration due to gravity = g = 10 ms-2
  • Mass of Rani = ?

Working Formula:
W = mg

Calculation:
450 = m (10)
m = 450/10 = 45 kg
Ans: Hence her mass is 45 kg.

7. Weight of Naveera is 700 N on the Earth's surface. What will be Naveera's weight at the surface of Moon?
Solution:
Data:
  • Weight of Naveera on the Earth's surface = WE = 700 N
  • Acceleration due to gravity on the surface of Earth = gE = 10 Nkg-1
  • Acceleration due to gravity on the surface of Moon = gM = 1.6 Nkg-1
  • Naveera's weight at the surface of Moon = WM = ?

Working Formula:
W = mg

Calculation:
To calculate Naveera's weight at the surface of Moon, We need to find her mass. To find her mass we apply the formula:
WE = mgE
700 = m (10)
m = 700 / 10 = 70 kg

Now, to find her weight at the surface of Moon,
WM = mgM
WM = 70 x 1.6 = 112 N

Ans: Hence Naveera's weight at the surface of Moon will be 112 N.

Mass of Earth
10. If “M ” is the mass of Earth, “R ” radius of Earth, “G” is universal gravitational constant, then find acceleration due to gravity “g”;
i) On the surface of Earth.
ii) At the centre of Earth.

Solution:
i) On the surface of Earth:
We consider a body of mass 'm' on the earth's surface. The gravitational force of attraction between the body and the earth are equal to the weight of the body.


ii) At the centre of Earth:
The force due to any portion of the Earth at the centre will be cancelled due to the portion opposite to it. Thus, the gravitational force at the centre on any body will be 0. Since, from Newton's law, we know F = mg. Since the mass m of an object can never be 0. Therefore, when F = 0, then g has to be 0. Thus the value of g is zero at the centre of the Earth.


11. A planet has mass four times of Earth and radius two times that of Earth. If the value of “g” on the surface of Earth is 10 ms–2. Calculate acceleration due to gravity on the planet.
Solution:
Data:
  • Mass of the planet = Mp = 4Me
  • Radius of the planet = rp = 2Re
  • Acceleration due to gravity on the surface of Earth = g = 10 ms–2
  • Acceleration due to gravity on the surface of Earth = gp = ?


Artificial Satellite
13.a) Calculate the speed of a satellite which orbits the Earth at an altitude of 400 kilometers above Earth's surface.
Solution:
Data:
  • Mass = MEarth = M = 6.0 x 1024 kg
  • Radius = REarth = R = 6.38 x 106 m
  • Altitude = h = 400 km = 400 x 103 m = 4 x 105 m
  • Universal gravitation = 6.673 x 10-11 Nm2kg-2
  • v =?


Ans: Hence, the orbital speed of satellite is 5.905 x 107 ms-1



Self Assessment Questions

Q.5: The strength of gravity on the Moon is 1.6 N kg-1 . If an astronaut’s mass is 80 kg on Earth, what would it be (weight) on the Moon?
Solution:
Data:
  • g = 1.6 N kg-1
  • m = 80 kg
  • W = ?

Working Formula:
W = mg

Calculation:
W = 80 x 1.6 = 128 N

Ans: Hence, The weight of the astronaut on the moon is 128 N.

Q.7: What will be the value of acceleration due to gravity on the surface of earth if its radius reduces to half?
Solution:


Q.8: What will be acceleration due to gravity on the surface of earth f its mass reduces by 25%?
Solution:


Q.9: What will be the mass of a planet whose radius is 20% of the radius of earth?
Solution:


Activity (Text book Pg No. 143)

1. Calculate the mass of the Earth if acceleration due to gravity; g = 9.8 ms–2.
Solution:
Data:
  • g = 9.8 ms–2.
  • RE = 6.38 x 106m
  • G = 6.673 x 10-11Nm2kg-2
  • M
ME = 6.0 x 1024 kg
Ans: Hence, the mass of Earth is 6.0 x 1024 kg.




Saturday 12 February 2022

Gravitation - Physics For Class IX (Science Group) - Question Answers

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Physics For Class IX (Science Group)
UNIT 6: GRAVITATION
Questions Answers


Q.No.1: State Newton's Law of gravitation. Derive the equation,  F = G m1m2/r2
Ans: NEWTON'S LAW OF GRAVITATION:
Sir Isaac Newton, was one of the greatest scientist of the world. He made fundamental contributions not only to several branches of Physics (like optics and mechanics) but also to Astronomy and Mathematics. He formulated the laws of motion and law of Universal gravitation.

Statement Of Newton’s Law Of Gravitation:
Newton's law of universal gravitation states that:
"Everybody in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres."

Derivation of Newton's Law Of Gravitation:
To understand this law, let us consider two bodies of masses m1 and m2. The distance between their centers is r.
According to the statement force of attraction between two bodies is directly proportional to the product of their masses.

Therefore,
F ∝ m1 m2 ------- (i)

The gravitational force of attraction is inversely proportional to the square of the distance between the centers of the masses of the bodies. Therefore


Where 'G' is constant of proportionality known as “Universal gravitational constant” or Newtonian constant of gravitation or the Cavendish gravitational constant.

Unit Of Universal Gravitational Constant:
The value of ‘G’ in SI unit is 6.673 x10-11 Nm2kg-2. This is very small value. ‘G’ remains constant everywhere.

We do not feel the gravitational force of attraction between objects around us due to the very small value of 'G'. But it exists everywhere in the universe.


Q.2: What is gravity? How does it act on objects? Does the pull of the gravity affect the Moon?
Ans: GRAVITY:
‘Gravity’ is taken from Latin word ‘gravitas’ means ‘weight’.
"The natural force which pulls every two objects in the universe towards each other is known as “Gravity”.
OR
"The gravitational force (pull) of Earth is known as gravity."

Affect Of Gravity On Objects:
  • This force acts on all objects which have mass.
  • This force depends upon the masses of the objects. Big masses have high gravitational pull while small masses have low gravitational pull.
  • Gravity of earth hold all objects like buildings, animals, trees, human beings etc on Earth.
  • Moon, stars and planets all have gravity.
  • The gravity causes weight.
  • The weight of an object is smaller at moon than Earth.
  • Gravity causes the satellites and planets to move in their orbits.

Demonstration Of Newton’s Law Of Universal Gravitation With The Path Of The Moon:
The pull of the gravity also affect the moon. It changes the path of the Moon, which revolve the Moon around the Earth.
In other words, the Earth's gravity keeps the Moon orbiting us. It keeps changing the direction of the Moon's velocity. This means gravity makes the Moon accelerate all the time, even though its speed remains constant.


Q.3: How did Newton explore the idea of gravity?
Ans: In 1666, One day Isaac Newton was sitting in his mother’s, garden where he witnessed an apple falling from a tree. The scenario helped him to explore the idea of gravity. Newton successfully discovered the cause of falling bodies. He further revealed that gravity makes the planets to revolve around the sun and it also causes the moon and satellite orbiting around the earth in a specific fashion.

Q.4: Difference between “G” and “g”.
Ans: Difference Between “G” And “g”:
S.NO. “G” “g”
1. It is a universal gravitational constant. It is the acceleration due to gravity which determines the gravitational force acting per unit mass.
2. It has same value everywhere in the universe. It has different values at different places.
3. It has value 6.673 x10-11 Nm2kg-2 Near the earth's surface, it has a value 10 ms-2 or 10 Nkg-1.


Q.5: Write down the characteristics / key points of gravitational force?
Ans: CHARACTERISTICS / KEY POINTS OF GRAVITATIONAL FORCE:
Gravitational force has following characteristics:
  1. It is always present between every two objects because of their masses.
  2. It exists everywhere in the universe.
  3. It forms an action-reaction pair.
  4. It is independent of the medium between the objects.
  5. It is directly proportional to the product of the masses of objects.
  6. It is inversely proportional to the square of the distance between the centres of the objects.
  7. Hence it follows the “Inverse Square Law”.

Q.6: Explain that the gravitational forces are consistent with Newton's third law. Or Is Newton's law of gravitation consistent with Newton's third law of motion?
Ans: Law of Gravitation and Newton’s Third law of Motion:
According to Newton's law of gravitation,
every two objects attract each other with equal force but in opposite direction.
Suppose
  • m1 ⟶ Mass of body A
  • m2 ⟶ Mass of body B
  • F12 ⟶ Force with which body A attracts body B
  • F21 ⟶ Force with which body B attracts body A
Then according to this law
F12 = -F21
This shows that, the two forces are equal in magnitude but opposite in direction. Now, if F12 is considered as “Action Force” and F21 as “Reaction Force”. Then by using above equation, it is concluded that: 
“Action equals to reaction but in opposite direction”.
OR
Gravitational force forms an action-reaction pair.
As we know that, above statement is in accordance with the Newton's third law of motion which states that
“To every action there is always an equal and opposite reaction”.
Hence, Newton's law of gravitation is consistent with Newton's third law of motion.
For example:
According to Newton's law of Universal gravitation the Earth pulls the Moon with its gravity and the Moon pulls the Earth with its gravity. Therefore they form an action-reaction pair, which is in accordance with Newton's third law of motion.


Q.7: Define gravitational field. Describe the Earth's gravitational field. OR Explain gravitational field as an example of field of force.
Ans: GRAVITATIONAL FIELD:
Gravitational field can be described as:
“A gravitational field is a region in which a mass experiences a force due to gravitational attraction”.

Earth's Gravitational Field:
The earth has an attractive gravitational field around it. Any object near the Earth experience this force which is due to Earth's gravity. This field is directed towards the centre of the Earth.
Field force Of Earth's Gravitational Field:
The force of this field is strongest near the surface of the Earth and gets weaker as we move farther and farther away from the Earth. This force is called the “Field Force” because it acts on all objects whether they are in contact with Earth's surface or not. So, it is a non-contact force.
For example,
It acts on an aeroplane either it is standing on Earth's surface or flying in the sky.

Gravitational Field Strength:
A body of mass one kilogram (1 kg) on Earth experiences a force of about ten newton (10 N) due to Earth's gravitational field. This force determines the gravitational field strength which is defined as:
"Gravitational field strength ‘g’ is the gravitational force acting per unit mass."
The gravitational field strength “g” is approximately 10 Newton per kilogram or 10 Nkg-1. The gravitational field strength “g” is different at different planets.
For example,
The gravitational field strength “g” on the surface of Moon is approximately 1.6 Newton per Kilogram 1.6 Nkg-1.

Gravitational Field Strength Of Different Planets:
Acceleration due to gravity “g” at different planets are as follows:
Planet Value of g ms-2
 Earth10
 Moon1.62
 Venus8.87
 Mars3.77
 Jupiter25.95
 Sun274
 Mercury3.59
 Saturn11.08
 Uranus10.67
 Neptune14.07



Q.8: Define weight? What instrument is used to measure the weight of an object? OR Define weight (as the force on an object due to a gravitational field.)
Ans: WEIGHT:
All the objects which are thrown upward in the air, fall back to the ground.
The force applied by the Earth's gravitational field, pulls the objects downward. Weight is another name for the Earth's gravitational force on the objects. Because ‘gravity’ is taken from Latin word ‘gravitas’ means ‘weight’.
Therefore weight can be defined as:
"The weight of an object is the measurement of gravitational force acting on the object."
OR
"Weight of an object is the gravitational pull of Earth acting on it."
Weight 'W' of an object of mass 'm', in a gravitational field of strength 'g' is given by the relation:
W = mg .......... (i)

Unit Of Weight:
Like other forces, weight is a vector quantity and is also measured in Newton's (N).

Instrument Use To Measure Weight:
Spring balance:
is used to measure weight of an object.
An object of mass 1 kg has a weight of 9.8 N near the surface of Earth. The objects with larger masses may have larger weights. Our weight vary slightly from place to place, because Earth's gravitational field strength varies at different places. The weight of the object changes as it moves away from the Earth. The weight of the object is different at different planets.
For example:
We will have less weight at Moon because Moon's gravitational field is weaker than Earth.


Q.9: What is "Atwood machine"?
Ans: ATWOOD MACHINE:
British scientist George Atwood (1746-1807) used two masses suspended from a fixed pulley, to study the motion and measure the value of ‘g’. This is named as “Atwood Machine”.


Q.10: By using Newton's Law of Gravitation, find the mass of the earth?
Ans: MASS OF THE EARTH:
Mass of Earth can not be measured directly by placing it on any weighing scale. But it can be measured by an indirect method. This method utilizes the Newton's law of universal gravitation.
Let us consider a small ball is placed on the surface of Earth.
  • m ⟶ Mass of the ball.
  • ME ⟶ Mass of Earth.
  • G ⟶ Universal gravitational constant.
  • Rg ⟶ Radius of earth; which is also the distance between the ball and centre of earth.
Then according to Newton's law of universal gravitation, the gravitational force F of the Earth acts on the ball is:


Whereas the force with which Earth attracts the ball towards its centre is equal to the weight of the ball.
Therefore,
F = W = mg ............. (ii)
Comparing equation (i) and (ii); we get:


Numerical values of the constants at right hand side of equation (iii) are:
g = 10 Nkg-1
RE = 6.38 x 106m
G = 6.673 x 10-11Nm2kg-2
Substituting these values in equation (iii), we get:


ME = 6.0 x 1024kg.
Thus, mass of Earth is 6.0 x 1024kg.


Q.11: What are satellites? Define its types?
Ans: SATELLITES:
A satellite is an object that revolves around a planet. Satellites are of two types:
  1. Natural satellites
  2. Artificial satellites

1. Natural satellites:
The planet which revolves around another planet naturally is called “Natural Satellite”.
E.g: Moon is a natural satellite because it revolves around the Earth naturally.

2. Artificial Satellites:
The object which are sent into space by scientists to revolve around the Earth or other planets are called “Artificial Satellite”.
E.g. Sputnik-1, Meteosat, Explorer-1 are amongst the artificial satellites.
Sputnik-1 was the first artificial satellite which was sent into space by Soviet Union (Russia) on 4th October 1957.


Q.12: What are the uses of artificial satellite? OR Write down any four uses of artificial satellite.
Ans: USES OF ARTIFICIAL SATELLITE:
Artificial satellites are used for different purposes like:
  1. For communication.
  2. For making star maps.
  3. For making maps of planetary surfaces.
  4. For collecting information about weather.
  5. For taking pictures of planets, etc.
Artificial satellites carry instruments, passengers or both to perform different experiments in space.

Q.13: What do you know about the orbits of artificial satellite?
Ans: ORBITS OF ARTIFICIAL SATELLITE:
Artificial satellites have been launched into different orbits around the Earth. There are different types of orbits like:
  1. For communication.
  2. Low- Earth orbit.
  3. Medium- Earth orbit.
  4. Geostationary orbit.
  5. Elliptic orbit.

CHARACTERS OF ORBITS:
These orbits are characterized on the basis of different parameters like,
  • Their distance from the Earth,
  • Their time period around the Earth etc.

Q.14: Describe communication satellite and geostationary orbit?
Ans: COMMUNICATION SATELLITE:
An artificial satellite which completes its one revolution around the Earth in 24 hours is used for communication purpose. As it is used for communication purpose, therefore it is known as “Communication Satellite”.

GEOSTATIONARY ORBIT:
A communication  satellite completes its one revolution around the Earth in 24 hours. As Earth also completes its one rotation about its axis in 24 hours, therefore the communication satellite appears to be stationary with respect to Earth. The orbit of communication satellite is therefore called “Geostationary orbit”. The height of a geostationary satellite is about 42,300 km from the surface of the Earth. Its velocity with respect to Earth is zero.

Q.15: Define orbit?
Ans: ORBIT:
The curved path along which a natural or artificial satellite revolves around a planet is called an “orbit”;. Rockets are used to put satellites into orbits in space.


Q.16: Discuss the importance of Newton's law of gravitation in understanding the motion of satellites? OR Derive the expression for the velocity and time period of a satellite that orbiting around the Esarth?
Ans: Importance Of Newton’s Law of Gravitation in the motion of satellite:
The Newton's law of gravitation has an important role in the motion of satellite in its orbit, because the gravitational pull of Earth on the satellite provides the centripetal force needed to keep a satellite in orbit around some planet.

Expression For The Velocity That A Satellite Possess When Orbiting Around The Earth:
Let us consider the motion of a satellite which is revolving around the Earth:

  • m ⟶ Mass of the satellite.
  • M ⟶ Mass of Earth.
  • R ⟶ Radius of Earth
  • h ⟶ Height (altitude) of satellite from the surface of Earth.
  • r = R + h ⟶ Radius of orbit.
Then, as we already discussed:


This gives the velocity that a satellite must possess when orbiting around Earth in an orbit of radius (r = R+h).
This shows that, the speed of the satellite is independent of its mass. Hence every satellite whether it is very massive (large) or very light (small) has the same speed in the same orbit.

Expression For The Time Period Of A Satellite Orbiting Around The Earth:
The time required for a satellite to complete one revolution around the Earth in its orbit is called its time period “T”. The time period of a satellite can be calculated as:


Equations (iv) gives the expression for the time period of a satellite orbiting around the Earth. Thus, Newton's law of gravitation helps to describe the motion of a satellite in an orbit around the Earth.

Q.17: Describe the motion of artificial satellite around the Earth.
Ans: Motion of Artificial Satellite around the Earth:
The satellites are put into their orbits around the Earth by rockets. When a satellite is put into orbit, its speed is selected carefully and correctly. If speed is not chosen correctly then the satellite may fall back to Earth or its path may take it further into orbit. During the motion of a satellite in the orbit the gravitation pull of Earth on it is always directed towards the centre of Earth.
Newton used the following example to explain how gravity makes the orbiting possible.
Let us imagine a cannonball launched from a high mountain, three paths the ball can follow are:
Path A Path B Path C
 The canon ball is launched at a slow speed. The canon ball is launched at a medium speed. The canon ball is launched at a high speed.
 The canon ball will fall back to Earth. The canon ball will fall back to Earth. The canon ball will not fall back to Earth instead it orbits around the Earth.

Above example shows that, for an artificial satellite to orbit the Earth and to retrace its path it requires certain orbital velocity.


Q.18: Define orbital velocity? Derive an expression for the orbital velocity of an artificial satellite?
Ans: ORBITAL VELOCITY:
The orbital velocity is defined as:
"The velocity required to keep the satellite into its orbit is called “Orbital Velocity”.

Expression for the orbital velocity of an artificial satellite:
The gravitational pull of Earth on a satellite provides the necessary centripetal force for orbital motion. Since this force is equal to the weight of satellite,
‘WS = mg’, therefore
FC = WS ........ (i)
and,  WS = mgh

where,
  • m ⟶ Mass of the satellite.
  • gh ⟶ Acceleration due to gravity at height ‘h’ from the surface of Earth.
The centripetal force ‘FC ’ on the satellite is:


If satellite is orbiting very close to the surface of Earth
then: h << R
In this case orbital radius may be considered equal to radius of Earth.
Therefore, R + h = R
Also gh = g
and v = vc
Where,
  • vc ⟶ Critical velocity
  • g ⟶ Acceleration due to gravity on the surface of Earth.
In terms of above factors equation (ii) becomes:
vc = √ gR ........ (iii)
This is known as “Critical velocity”.
It is defined as:
"The constant horizontal velocity required to put the satellite into a stable circular orbit around the Earth."
It is also known as orbital speed or proper speed.
If
g = 10 ms-2
R = 6.38 106 m
Then equation (iii) becomes.
vc = √ gR = √ 10 ms-2 x 6.38 106 m
vc = √ 7.99 x 103 ms-1
vc = 8.0 kms-1
It should be noted that as the satellite get closer to the Earth, the gravitational pull of the Earth on it gets stronger.
So, the satellites in order to stay in an orbit closer to Earth needs to travel faster as compare to those satellites in the farther orbits.

Q.19: How would the value of "g" and "G" be affected, if the mass of the earth becomes four times!
Ans: (i) For "g":

As  g = GMe / Re2

It means that "g" is directly proportional to the mass of the earth if the mass of the earth decrease, the value of "g" will also decreases. If the mass of the earth increases the value of "g" will also increases. If the mass of the earth becomes four times the value of "g", g will also become four times. It means "g" will increase four times.'

(ii) For "G":
"G" is a universal gravitational constant it remains the same through out the universe. If the mass of the earth becomes four times the value of "G" will not change. It will remain the same as it is a constant. Its value is 6.673 x 10-11 Nm2Kg-2.

Point to Ponder

Does the whole solar system works in a push and pull network?
Ans: Gravity keeps things together. It is a force that attracts matter towards it. Anything with mass creates gravity, but the amount of gravity is proportional to the amount of mass. Therefore, Jupiter has a stronger gravitational pull than Mercury. Distance also affects the strength of the gravitational force. Therefore, the Earth has a stronger pull on us than Jupiter does, even though Jupiter is as big as over 1,300 Earths. While we are familiar with gravity's impact on us and Earth, this force also has many effects on the entire solar system, too.

Creates Orbit:
One of the most noticeable effects of gravity in the solar system is the orbit of the planets. The sun could hold 1.3 million Earths so its mass has a strong gravitational pull. When a planet tries to go past the sun at a high rate of speed, gravity grabs the planet and pulls it towards the sun. Likewise. the planet's gravity is trying to pull the sun towards it but can't because of the vast difference in mass. The planet keeps moving but is always caught up in the push-pull forces caused by the interaction of these gravitational forces. As a result, the planet begins orbiting the sun The same phenomenon causes the moon to orbit around the Earth except for the Earth's gravitational force, not the sun's that keeps it moving around us.

Tidal Heating:
Just as the moon orbits the Earth, other planets have moons of their own. The push-pull relationship between the gravitational forces of the planets and their moons causes an effect known as tidal bulges. On Earth, we see these bulges as high and low tides because they occur over oceans. But on planets or moons without water, tidal bulges can occur over land. In some cases, the bulge created by gravity will be pulled back and forth because the orbit vanes in its distance from the primary source of gravity. The pulling causes friction and is known as tidal heating. On lo, one of Jupiter's moons, the tidal heating has caused volcanic activity. This heating may also be responsible for volcanic activity on Saturn's Enceladus and liquid water underground on Jupiter's Europa.

Creating Stars:
Giant molecular clouds made up of gas and dust slowly collapse because of the inward pull of their gravity. When these clouds collapse, they form lots of smaller areas of gas and dust that will eventually collapse as well. When these fragments collapse, they form stars. Because the fragments from the original GMC stay in the same general area, their collapse causes stars to form clusters.

Formation of Planets:
When a star is born, all of the dust and gas not needed in its formation ends up trapped in the orbit of the star. The dust particles have more mass than the gas so they can begin to concentrate in certain areas where they come in contact with other dust grains. These grains are pulled together by their own gravitational forces and kept in orbit by the gravity of the star. As the collection of grains becomes bigger, other forces also begin to act upon it until a planet forms over a very long period of time.

Destruction Cause:
Because many things in the solar system are held together thanks to the gravitational pull among its components, strong external gravitational forces could pull those components apart thus destroying the object. This happens with moons sometimes. For example, Neptune's Tnton is being pulled closer and closer to the planet as it orbits. When the moon gets too close, perhaps in 100 million to 1 billion years, the planet's gravity will pull the moon apart. This effect might also explain the origin of the debris that makes up the rings found around all of the large planets: Jupiter, Saturn, and Uranus.





Friday 11 February 2022

Islamiat (اسلامیات) For Class IX -New - Baab So'um: Mozuaati Mutalah - (ج) Siraat e Tayyabah - Munaqeeb e Sahaba' e Karaam Aur Ashara Mubashra (رضی الله عنھہ) - Short Question-Answers

باب سوم: موضوعاتی مطالعہ
(ج) سیرت طیبہ - 5- مناقب صحابہ کرام اور عشرہ مبشرہ کرام رضی الله عنھہ
کثیرالانتخابی سوالات






Islamiat (اسلامیات) For Class IX -New - Baab So'um: Mozuaati Mutalah - (ج) Siraat e Tayyabah - Munaqeeb e Sahaba' e Karaam Aur Ashara Mubashra (رضی الله عنھہ) - Detailed Question-Answers

باب سوم: موضوعاتی مطالعہ
(ج) سیرت طیبہ - 5- مناقب صحابہ کرام اور عشرہ مبشرہ کرام رضی الله عنھہ
کثیرالانتخابی سوالات





Islamiat (اسلامیات) For Class IX -New - Baab So'um: Mozuaati Mutalah - (ج) Siraat e Tayyabah - Munaqeeb e Sahaba' e Karaam Aur Ashara Mubashra (رضی الله عنھہ) - Multiple Choice Questions (MCQs) کثیرالانتخابی سوالات

باب سوم: موضوعاتی مطالعہ
(ج) سیرت طیبہ - 5- مناقب صحابہ کرام اور عشرہ مبشرہ کرام رضی الله عنھہ
کثیرالانتخابی سوالات






Tuesday 8 February 2022

Islamiat (اسلامیات) For Class IX -New - Baab So'um: Mozuaati Mutalah - (ج) Siraat e Tayyabah - Munaqeeb e Ehle Ba'it ithaar (رضی الله عنھہ) - Short Question-Answers

باب سوم: موضوعاتی مطالعہ
(ج) سیرت طیبہ - 5- مناقب اہل بیت اطہار رضی الله عنھہ
مختصر سوال و جواب


سوال نمبر 4: حدیث الکسار کی روشنی میں اہل بیت اطہار کے اسماء گرامی تحریر کریں؟
جواب: اہل بیت اطہار کے اسماء گرامی:
  1. سیدنا حضرت علی المرتضی رضی اللہ عنہ
  2. سیدہ فاطمۃ الزہراء رضی اللہ عنہا
  3. حضرت امام حسن رضی اللہ عنہ
  4. حضرت امام حسین رضی اللہ عنہ
(نوٹ: سوال نمبر 4 میں مختصر جواب کے لحاظ سے صرف نام لکھنے ہیں۔)





Islamiat (اسلامیات) For Class IX -New - Baab So'um: Mozuaati Mutalah - (ج) Siraat e Tayyabah - Munaqeeb e Ehle Ba'it ithaar (رضی الله عنھہ) - Detailed Question-Answers

باب سوم: موضوعاتی مطالعہ
(ج) سیرت طیبہ - 5- مناقب اہل بیت اطہار رضی الله عنھہ
تفصیلی سوال و جواب






Islamiat (اسلامیات) For Class IX -New - Baab So'um: Mozuaati Mutalah - (ج) Siraat e Tayyabah - Munaqeeb e Ehle Ba'it ithaar (رضی الله عنھہ) - Multiple Choice Questions (MCQs) کثیرالانتخابی سوالات

باب سوم: موضوعاتی مطالعہ
(ج) سیرت طیبہ - 5- مناقب اہل بیت اطہار رضی الله عنھہ
کثیرالانتخابی سوالات






Chemistry For Class IX (New Book ) - Chapter No. 8-Chemical Reactivity - Long Questions And Answers

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Chapter No.8-Chemical Reactivity
Detailed Questions And Answers


SECTION- C: DETAILED QUESTIONS:
1. Explain importance of Silver.
Ans: IMPORTANCE OR COMMERCIAL VALUE OF SILVER (Ag):
It is widely used in society.
  1. Jewelry: It is used in Jewelry, decorative items and Silver tableware because it does not tarnish and maintain its silvery shiny appearance.
  2. Mirror: It is used to make mirror because it is best reflector of visible light.
  3. Compounds: Silver forms compounds of significant importance.
  4. Detection Of Halogen: Silver Nitrate (AgNO3 ) or Lunar caustic is used in detection of Halogen.
  5. Photographic Film: Light sensitive material AgBr and AgI are used in Photographic films.

2. Explain importance of Gold.
Ans: IMPORTANCE OR COMMERCIAL VALUE OF GOLD (Au):
Gold has importance in our society.
  1. Jewelry: It is used in Jewellery because it has very high luster, yellow colour and tarnish resistance.
  2. Electronic Components: Gold is used in Electronic components because it is highly efficient conductor of current and cannot corrode.
    (a) Cables: Gold is used in connecting wires, connection strips, switches and relay contacts to make electronic devices highly reliable.
    (b) Electronic Devices:
    (i) Gold is used in cellphones, global positioning systems, Calculators etc.
    (ii) Gold is used in Laptop, Computers for rapid and accurate transmission of digital information.
  3. Dentistry: It is used in dentistry because it is chemically inert, non-allergic and easy for dentist to work.
  4. Space vehicles: Gold coated polyester films are used in space vehicles to reflect infrared radiation and stabilize the temperature of space vehicle.
  5. Helmet Of Astronaut: The helmet of Astronaut is coated with thin film of gold which reflect intense Solar radiation and protect eyes, skin of astronaut.
  6. Coating Of Glass: Glass surface coated with gold will reflect solar radiations outward and keep the Buildings cool in summer. It also reflects internal heat inward and keeps the Building warm in winter.
  7. Awards And Trophies: Gold symbolizes purity, beauty and stability so it is used in making medals, trophies awards etc.

3. Explain the experiment to test Cl- and I- ions.
Ans: Test For Cl-1:
Experiment Observation Result
Few ml of salt solution + dilute HNO3 + AgNO3 White pptCl-1 may be present.
White ppt + NH4OH solutionWhite ppt soluble in NH4OHCl-1 Ion is present.


Test For I-1:
Experiment Observation Result
Few ml of salt solution + dilute HNO3 + AgNO3 Yellow pptI-1 ion may be present.
Yellow ppt + NH4OH solutionYellow ppt insoluble in excess NH4OHI-1 Ion is present.


4. Explain Electropositive character of metals.
Ans: ELECTROPOSITIVE CHARACTERS OF METALS (Cation formation):
Metals are highly electro positive, due to this property they easily lose their valance shell electrons and form cations.
Cations:
When an atom or a molecule loses electron then it changes into positively charged ion known as Cation.
Example:
Al ⟶ Al3+ + 3e-

Reactivity:
Electro positive character of metals increases down the group with increasing atomic size.
Alkali metals have large atomic size and low ionization potential values. The nucleus force on valence shell is very weak so they can lose their valence electron easily. Hence they are highly reactive, highly electro positive, powerful reducing agents and cannot exist free in nature.

5. Explain the position of Magnesium in periodic table and its importance. OR Describe the position of magnesium in Periodic Table, their simple properties and uses.
Ans: MAGNESIUM (Mg):
Position:
  • It is 8 most abundant element found in earth's crust.
  • Magnesium belongs to II-A group and 3rd period of periodic table.

Properties:
Physical properties:
  • It is a grey-white metal.
  • Its name is derived from Magnesia, a district in Greece.
  • It melts at 650 °C and boils at 1090 °C.

Chemical Properties:
1. Reaction With Water:
Magnesium reacts violently with water and releases Hydrogen gas.
Mg + 2H2 O → Mg (OH)2 + H2

Magnesium fire cannot be extinguished with water because H2 gas is highly flammable and intensifies the fire. Magnesium fire can be extinguished by using dry sand.

Uses:
  1. It is used in flares and photographic flash bulbs because it burns to produce brilliant white light.
  2. Magnesium hydroxide are used as an Antacid.
  3. It is used for manufacturing of Mobile Phones, Laptop and Tablet Computers because of light weight and electrical properties.
  4. The use of Magnesium reduces the weight of vehicle by replacing steel components of a vehicle.
  5. Magnesium alloys are used in aviation industry, space crafts and missile because they are light weight and remain stable at high temperature.
  6. Magnesium can be changed into intricate (twisters, knotty) shapes, so it is used in tenis, rackets and handles of archery bows.
  7. Magnesium is used in cathodic protection (CP) to protect underground pipeline from corrosions.

6. Explain the position of Sodium in periodic table and its importance. Also write down its properties. OR Describe the position of sodium in Periodic Table, its simple properties and uses?
Ans: SODIUM (Na):
Position:
  • It is sixth most abundant element and constitutes 2.87% of earth's crust.
  • It belongs to I A group and 3rd period of periodic table.

Properties:
Physical Properties:
  1. Sodium is silvery white alkali metal.
  2. It melts at 97.8 °C and boils at 881.4 °C.
  3. It is soft and can be cut with Knife due to weak metallic bonding between their atoms.

Chemical Properties:
  1. Reaction with water:
    It violently reacts with H2O water and form Sodium Hydroxide (NaOH) and Hydrogen (H2) gas, so it is kept in kerosene oil to prevent its reaction with moisture.
    2Na + 2H2O ⟶ 2NaOH + H2

  2. Reaction With Oxygen:
    Sodium metal has shining surface but its appearance becomes dull due to action of air.
    2Na + O2 ⟶ Na2O2

  3. Reaction With Halogens:
    Sodium reacts with halogens to form sodium halide.
    2Na + Br2 ⟶ 2NaBr

  4. Reaction With Acid:
    Sodium reacts with sulphuric acid to form H2 gas.
    2Na + H2SO4 ⟶ Na2SO4 + H2

Uses:
  1. It is an excellent heat transfer fluid so its used as coolent in nuclear reactors.
  2. It is used in Detergent preparation.
  3. It is used as Street lights and gives yellow colour.
  4. It is used as Reducing agent in the extraction of Calcium, Zirconium and Titanium.
  5. Sodium form useful compounds, such as
    (i) Soda ash (Na2CO3) Used as water softener.
    (ii) Baking Soda (NaHCO3) Used in Baking Powder, Health Salt, Beverages
    (iii) Table Salt (NaCl): Food Items.
    (iv) Sodium Nitrate (NaNO3): Used as fertilizer and in Dynamite

7. Arrange the following Halogen Acids in increasing order of their Acidic strength: HBr, HCI, HI, HF.
Ans: The Acidic strength of Halogen Acid decreases in the following order:
HI > HBr > HCl > HF
  • HI is very strong acid because HI easily breaks up and forms H+ Ion in water due to weak Covalent Bonding.
  • HF is very weak acid because it has strong Covalent Bonding so it does not break up easily to form H+ Ion in water.


8. Explain electronegative character of non-metals.
Ans: ELECTRONEGATIVE CHARACTERS OF NON-METALS:
A Non-metal has property to accept electron easily and form Anion. It is called electronegative character.
x + e- → x-
Electronegative character increases across the period because Atomic size decreases and nuclear charge density increases. It decreases down the group due to increasing Atomic size.
Example:
Halogens accept electrons easily due to their high electronegative character.
Cl+ e- → Cl-


9. Differentiate between sodium and iron as soft and hard metals. or Differentiate between soft and hard metals (Iron and Sodium).
Ans: Difference Between Soft And Hard Metals (Iron and Sodium):
Soft and hard metals can be differentiated with reference to sodium (Na) and iron (Fe) as follows:
S.NO. Sodium Iron
1. It is a soft metal of group I A. It is a hard metal VIII B
2. It has large atomic size. It has smaller ionic radii.
3. It has low value (0.5) on moh scale.  It has high value (4.5) on moh scale.
4. It has weak metallic bonding so it is a soft metal It has strong metallic bonding so it is hard metal.
5. It can be cut easily with knife. It is hammered to form sheets and wires.
6. It is light due to its low density (0.971 g/cm3). It is heavier metal due to its high density (7.87 g/cm3 ).
7. It has low melting and boiling point values:
(melting point = 98 °C,  boiling point = 890 °C)
 It has high melting and boiling point values:
(melting point = 1535 °C, boiling point = 2450 °C)


Q.10: Discuss the reactivity of Halogen? OR Compile some important reactions of halogens.
Ans: REACTIVITY OF HALOGENS:
Halogen belongs to VII-A group and consists of:
  1. Fluorine (F),
  2. Chlorine (Cl),
  3. Bromine (Br),
  4. Iodine (I) and
  5. Astatine (At).
Halogens exist in Molecular form. The reactivity of halogens decreases down the group because atomic size increases and electro negativity decreases down the group.

1. Act As Oxidizing Agent:
Halogens act as oxidizing agent, because they easily accept electron.
2Na + Cl2 → 2NaCl
2K + l2 → 2Kl

Power of Halogens as oxidizing agent decreases in the following order:
F2 > Cl2 > Br2 > I2
It means Fluorine can displace other Halogens due to its highest oxidizing power.

2. Highly reactive Halogens Replace Less Reactive halogens:
More reactive Halogen can displace less reactive Halogen form a solution of its salt.
Example:
  • 2KI + Cl2 → 2KCl + I2
    Chlorine is more reactive Halogen than Iodine so Chlorine displaces Iodine. The mixture turns reddish brown due to liberation of Iodine.

  • 2KCl + F2 → 2KF + Cl2

  • 2KBr + F2 → 2KF + Br2

3. Reaction With Hydrogen:
Reaction of Hydrogen with Halogen form Halogen acid.
H2 + X2 ⟶ 2HX
Where,
  • (X2 = F2, Cl2, Br2, I2)
  • (HX = HF, HCl, HBr, HI)
The Acidic strength of Halogen Acid decreases in the following order:
HI > HBr > HCl > HF
  • HI is very strong acid because HI easily breaks up and forms H+ Ion in water due to weak Covalent Bonding.
  • HF is very weak acid because it has strong Covalent Bonding so it does not break up easily to form H+ Ion in water.
  • H+ Ions reacts with water molecule to forms Hydronium (H3O )+

More Questions From Text Book

Q.1: Define element? What are the different type of elements Or Classifying the type of elements into metals, non-metals and metalloids.?
Ans: ELEMENT:
An element is always composed of like atoms.
Example:
Hydrogen (H2), Carbon (C), Oxygen (O2)

Types of elements:
Elements are further divided into:
  • Metals,
  • Non-metals and
  • Metalloids

METALS:
"The element which readily loses electron in reaction and easily form cation is termed as metal."
Properties:
  • A metal structure consists of metal ions joined by metallic bonds.
  • Metals are good conductors of heat and electricity.
  • They are Ductile, Strong, Lustrous, Malleable and Sonorous.
  • Metals have low electro-negativity.
  • They have high melting points.
  • They are solid.
  • Oxides of metals are basic in nature e.g. (Li2O, Na2O2 ,KO2 ,MgO).

Examples:
  • All B group elements are metals and known as Transition Metals. e.g Iron (Fe), Copper (Cu), Zinc (Zn) etc.
  • Some elements of A group are also metals.
    (i) Elements of group I A are called Alkali metals. e.g: Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs) and Francium (Fr).
    (ii) Elements of group II A are called Alkaline earth metals. e.g Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), Ba (Barium), Radium (Ra).


NON-METALS:
"Non-metals are the elements which have greater tendency to accept or gain electron in reaction and form anion are termed as non-metals."
Non-metals are placed at upper right portion of periodic table.
Properties:
  • They are poor or nonconductors of heat and electricity.
  • Non-metals are non malleable; non ductile, dull in appearance, non-sonorous.
  • Non-Metals have high electro-negativity.
  • They have low melting point.
  • They are solids and gases.
  • Oxides of non-metals are acidic in nature e.g. (CO2 , SO3 , NO2).

Examples:
  • Most of the non-metals are gases For example: H (Hydrogen), N (Nitrogen), O(Oxygen), F(Fluorine), Cl (Chlorine) and VIIIA group non-metals are gases.
  • Bromine (Br) is the only non-metal found in liquid state.
  • Some non metals like S (Sulphur), P (Phosphorus), Se (Selenium), I (Iodine) are solids.


METALLOIDS:
"Elements having intermediate properties of metals and non-metals. are termed as metalloids."
Properties:
  • Oxides of metalloids may be acidic (B2O3 , SiO2) or amphoteric (AS2O3).
Example:
  • Boron (B), Silicon (Si), Germanium (Ge), Arsenic (As), Antimony (Sb), Tellurium (Te), Polonium (Po) and Astatine (At) are metalloids.

Q.2: Define ionization energy? Explain the ionization energy of alkali and alkaline earth metals?
Ans: IONIZATION ENERGY:
The removal of electron from an element requires energy which is known as Ionization Energy or Ionization Potential.
Atom + Energy ⟶ Cation + e-
Ionization energies values decreases with increasing atomic size and vice versa.
Unit:
Ionization Potential Valence or unit of ionization energy is Kj/mole.

Ionization Energy of Alkali and Alkaline Earth Metal:
The Alkali metals and Alkaline earth metals show increasing trend of reactivity down the group because their atomic size increases down the group. Alkali Metals and Alkaline earth metals have low values of Ionization Energies due to which they easily lose their valence electron and form Cation. Thus they are highly reactive.

Alkali Metals Are Reactive Than Alkaline Earth Metals:
Since Alkali metals have low Ionization Energy values than Alkaline earth metals, so Alkali metals are highly reactive than Alkaline earth metals.


Q.3: How magnesium is used in cathodic protection (CP).
Ans: Cathodic Protection Of Magnesium:
Magnesium is easily oxidized as compared to iron so magnesium is used as anode and underground metallic pipelines become cathode to protect from corrosion.
Following reaction take place
Mg ⟶ Mg2+ + 2e- (Oxidation) (At Anode)
O2 + 4H+ + 4e- ⟶ 2H2(Reduction) (At Cathode)


Q.4: Describe the position of calcium in Periodic Table, their simple properties and uses.
Ans: CALCIUM (Ca):
Position:
  • It is 5th abundant metal in earth's crust.
  • It belongs to II A group and 4th period.

Properties:
Physical Properties:
  1. It is silvery white soft metal.
  2. It melts at 851 °C and boils at 1484 °C.

Uses:
  1. Calcium is essential for healthy teeth and bones.
  2. Calcium forms useful compounds, such as:
    (i) Slaked lime Ca(OH)2: As soil conditioner, used in water treatment to reduce acidity. Used in steel industry to remove impurities from Iron ore.
    (ii) Gypsum 2CaSO4.H2O: It is used as component in construction of buildings. It is used medically in plaster for setting broken bones.
    (iii) Calcium hypochlorite Ca(OCl)2: It is used for sterilization of water in swimming pool.
    (iv) Calcium tungsten CaWO4: It is used in Luminous paints.
    (v) Limestone CaCO3: As source of CO2, In Cement industry.

Q.5: Describe the commercial value of Platinum.
Ans: IMPORTANCE OR COMMERCIAL VALUE OF PLATINUM (Pt):
  1. It is a silvery white corrosion resistance metal.
  2. It is paramagnetic transition metal.
  3. It is used in chemical reactions as catalyst.
    Reaction:
    It is used as catalytic converter in vehicles. It helps the complete combustion of Hydrocarbons and reduces the emission of air pollutants.
  4. Price of precious metal is fixed according to its weight. Its density is more than Gold. So it is more expensive than Gold.

Q.6: Write down the qualitative analysis to identify the following cations like Zn+2, Mg+2, NH4+1, Ca+2 and Ba+2.
OR
Explain the experiment to test following cations: Zn+2, Mg+2, NH4+1, Ca+2 and Ba+2.


Ans: Qualitative analysis of Cations:
1. Test For Zn2+:
Experiment Observation Result
Salt Solution + NH4OH solution.White pptZn2+may be present
White ppt + excess NH4OH or NaOH solution.White ppt is dissolved and form clear solution.Zn2+ion is present .

2. Test For Mg+2:
Experiment Observation Result
Salt Solution + NaOH or NH40H solution.White pptMg2+may be present
White ppt + excess NH4OH / NaOH solution.White ppt insoluble in excess of NaOH or NH4OH Mg2+ion is present .


3. Test For NH4+1:
Experiment Observation Result
Portion of Aqueous solution of salt + NaOH solution warmPungent of NH3 Gas release NH4+ Ion is present


4. Test For Ba+2:
Experiment Observation Result
Heat Nichrome wire until flame is no longer coloured.Apple Green colour flame Ba2+ is present


5. Test For Ca+2:
Experiment Observation Result
Dip the loop of wire into water and then in unknown salt. Heat the wire on flame. Brick Red colour flameCa2+ is present


Q.7: Write down the qualitative analysis to identify the following anions like CO3-2, Cl-, I-+1, SO42- and NO2-.
OR
Explain the experiment to test following anions:
CO3-2, Cl-, I-+1, SO42- and NO2-.

Ans: Qualitative Analysis Of Anions:
1. Test For CO3-2:
Experiment Observation Result
Sample of Solid + Dilute Mineral AcidBubbles comes out which turns lime water milky.CO3-2 Ion is present


2. Test For Cl-1:
Experiment Observation Result
Few ml of salt solution + dilute HNO3 + AgNO3 White pptCl-1 may be present.
White ppt + NH4OH solutionWhite ppt soluble in NH4OHCl-1 Ion is present.


3. Test For I-1:
Experiment Observation Result
Few ml of salt solution + dilute HNO3 + AgNO3 Yellow pptI-1 ion may be present.
Yellow ppt + NH4OH solutionYellow ppt insoluble in excess NH4OHI-1 Ion is present.


4. Test For SO42-:
Experiment Observation Result
Few ml of Sample + dilute HCl + few drops of BaCl2
Or
Few drops of Sample of dilute HCI + few drops of lead nitrate Pb (NO3)2 soultion
White pptSO42- ion may be present.
White ppt + dilute HClWhite ppt insoluble in excess HCl SO42- Ion is present.


5. Test For NO2-:
Experiment Observation Result
Small amount of salt + few drops of dilute H2SO4 solutionReddish Brown vapours evolveNO2- ion is present.


Q.8: Draw flow chart diagram of classification of metals, non-metals and metalloids.
Ans: FLOW CHART: