Search This Blog

Thursday, 17 March 2022

Chemistry For Class IX (New Book ) - Chapter No. 5 - Physical States Of Matter - Numericals

GO TO INDEX

Chapter No.5- Physical States Of Matter
Numericals
Text Book Exercise

SECTION- D: NUMERICALS

1) Convert the following units:
(a) 100 °C to K
(b) 150 °C to K
(c) 780 K to °C
(d) 170 K to °C


Solution
a) 100 °C to K
Data:
  • Temperature in Celsius (C) = 100 °C
  • Temperature in Kelvin (K) = ?

Formula:
K = 273 + °C

Calculation:
K = 273 + 100 = 373 K Ans.

(b) 150 °C to K
Data:
  • Temperature in Celsius (C) = 150 °C
  • Temperature in Kelvin (K) = ?

Formula:
K = 273 + °C

Calculation:
K = 273 + 150 = 423 K Ans.

(c) 780 K to °C
Data:
  • Temperature in Kelvin (K) = 780 K
  • Temperature in Celsius (C) = ?

Formula:
°C = K - 273

Calculation:
°C = 780 - 273 = 507 °C Ans.

(d) 170 K to °C
Data:
  • Temperature in Kelvin (K) = 170 K
  • Temperature in Celsius (C) = ?

Formula:
°C = K - 273

Calculation:
°C = 170 - 273 = - 103 °C Ans.



More Numericals
Examples From Text Book



Examples 5.2: The 700 cm3 of a gas is enclosed in a container under a pressure of 650 mm of Hg. If the volume is reduced to 350 cm3, what will be the pressure then?
Solution:
Data:

  • V1 = 700 cm3
  • P1 = 650 mm
  • V2 = 350 cm3
  • P2 = ?

Formula:
P1 V1 = P2 V2


Examples 5.4: A sample of Hydrogen gas has a volume of 350 cm3 at 40 °C. If gas is allowed to expand up to 700 m3 at constant pressure. Find out its final temperature?
Solution:
Data:

  • T1 = 40 °C = 40+273 K = 313 K
  • V1= 350 cm3
  • V2= 700 cm3
  • T2 = ?




No comments:

Post a Comment